Lake Tașaul
(Redirected from Lake Taşaul)
| Lake Tașaul | |
|---|---|
  Lake Tașaul | |
| Location | Constanța County, Northern Dobruja |
| Coordinates | 44°21′00″N 28°36′48″E / 44.35000°N 28.61333°E |
| Primary inflows | Casimcea, Tașaul, Dalufac |
| Basin countries | Romania |
| Surface area | 23.35 km2 (9.02 sq mi) |
| Max. depth | 4 m (13 ft) |
| Surface elevation | 1 m (3.3 ft) |
Lake Tașaul (Romanian: Limanul Tașaul) is a lake in Northern Dobruja, Romania. Formerly an open salt water coastal lagoon, connected with the Black Sea, it was transformed into a freshwater lake in the 1920s. Its area is 23.35 km2 (9.02 sq mi) and its maximum depth is 4 m (13 ft).[1]
References
- ^ M.L. Alexandrov; J. Bloesch (2009). "Eutrophication of Lake Tașaul, Romania-proposals for rehabilitation". Environmental Science and Pollution Research. 16 (Suppl. 1): 42–45. doi:10.1007/s11356-008-0071-7. PMID 19132430. S2CID 39817102.
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