1895 Rhode Island gubernatorial election
Jump to navigation
Jump to search
![]() | |||||||||||||||||||||
| |||||||||||||||||||||
| |||||||||||||||||||||
|
Elections in Rhode Island |
---|
![]() |
The 1895 Rhode Island gubernatorial election was held on April 3, 1895. Republican nominee Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.89% of the vote.
General election
Candidates
Major party candidates
- Charles W. Lippitt, Republican
- George L. Littlefield, Democratic
Other candidates
- Smith Quimby, Prohibition
- George Boomer, Socialist Labor
- William Foster Jr., People's
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Charles W. Lippitt | 25,098 | 56.89% | ||
Democratic | George L. Littlefield | 14,289 | 32.39% | ||
Prohibition | Smith Quimby | 2,624 | 5.95% | ||
Socialist Labor | George Boomer | 1,730 | 3.92% | ||
Populist | William Foster Jr. | 379 | 0.86% | ||
Majority | 10,809 | ||||
Turnout | |||||
Republican hold | Swing |
References
- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 18, 2020.
Categories:
- Articles with short description
- Short description with empty Wikidata description
- Use mdy dates from September 2023
- Rhode Island gubernatorial elections
- 1895 United States gubernatorial elections
- 1895 Rhode Island elections
- April 1895 events
- 1895 in Rhode Island
- United States gubernatorial elections in the 1890s